Factor the expression by grouping. First, the expression needs to be rewritten as -4x^{2}+ax+bx-6. To find a and b, set up a system to be solved.

You are watching: What is the expression in factored form 4×2+11x+6

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

4×2+11x-69=0 Two solutions were found : x = -23/4 = -5.750 x = 3 Step by step solution : Step 1 :Equation at the end of step 1 : (22×2 + 11x) – 69 = 0 Step 2 :Trying to factor by …

Guilherme N. May 25, 2015 You can find its roots and then turn them into factors.Let's use Bhaskara to find them. displaystylefrac{{-{11}pmsqrt{{{121}-{4}{left({2}

ight)}{left(-{6}

ight)}}}}}{{4}} …

4×2+11x-3 Final result : (4x – 1) • (x + 3) Step by step solution : Step 1 :Equation at the end of step 1 : (22×2 + 11x) – 3 Step 2 :Trying to factor by splitting the middle term …

4×2+11x-3=0 Two solutions were found : x = -3 x = 1/4 = 0.250 Step by step solution : Step 1 :Equation at the end of step 1 : (22×2 + 11x) – 3 = 0 Step 2 :Trying to factor by splitting …

6×2+11x-32 Final result : 6×2 + 11x – 32 Step by step solution : Step 1 :Equation at the end of step 1 : ((2•3×2) + 11x) – 32 Step 2 :Trying to factor by splitting the middle term …

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displaystyle{f{{left({x}

ight)}}}={4}{left({x}^{{2}}+{3}{x}-{16}

ight)} Explanation: displaystyle{f{{left({x}

ight)}}}={4}{y}={4}{left({x}^{{2}}+{3}{x}-{16}

ight)} Factor y. displaystyle{D}={b}^{{2}}-{4}{a}{c}={9}+{64}={73} …

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Factor the expression by grouping. First, the expression needs to be rewritten as -4x^{2}+ax+bx-6. To find a and b, set up a system to be solved.

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=aleft(x-x_{1}

ight)left(x-x_{2}

ight), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: frac{-b±sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

Factor the original expression using ax^{2}+bx+c=aleft(x-x_{1}

ight)left(x-x_{2}

ight). Substitute frac{3}{4} for x_{1} and 2 for x_{2}.

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Subtract frac{3}{4} from x by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

left< egin{array} { l l } { 2 } & { 3 } \ { 5 } & { 4 } end{array}
ight> left< egin{array} { l l l } { 2 } & { 0 } & { 3 } \ { -1 } & { 1 } & { 5 } end{array}
ight>

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