A table tennis ball has an average density of 0.084 g/cm^3 and a diameter that 3.8 cm. What force can submerge the round in water? (density that water is 1 gm/cm^3) a) 1.0 N b) 0.79 N c) 0.52 N d) 0.26
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The density of the table tennis ball is 0.084 g/cm^3. This needs to be converted in terms of SI units. It is same to 0.084*10^-3/(0.01)^3 kg/m^3 = 84 kg/m^3. The thickness of water is 1 g/cm^3 i beg your pardon is equal to 1000 kg/m^3. The diameter of the tennis ball is 3.8...


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The thickness of the table tennis ball is 0.084 g/cm^3. This needs to be converted in terms of SI units. The is same to 0.084*10^-3/(0.01)^3 kg/m^3 = 84 kg/m^3. The thickness of water is 1 g/cm^3 which is same to 1000 kg/m^3. The diameter that the tennis ball is 3.8 cm or 0.038 m.

When a round is submerged in water, the pressure or resistance is equal to the load of the volume the water displaced from which the load of the ball is subtracted.

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Here, the pressure of resistance is (1000 - 84)*9.8*(4/3)*pi*(0.038/2)^3

=> 0.26 N

To submerge the ball, a force equal come the pressure of resistance has to be applied, i beg your pardon is same to 0.26 N

The exactly answer is alternative d. 0.26 N


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