An antelope moving with constant acceleration covers the distance between two points 70.0 m apart in 6.00 s. Its speed as it passes the second point is 15.0 m/s. What are (a) its speed at the first point and (b) its acceleration? ANSWER
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in this problem, we're asked for the initial velocity. So set the distance of the trip is seventy meters the time it takes to do the trip six seconds and the velocity at the end of the trip is fifteen years per second. To do this, we apply the magic equation X minus X not is equal to one half. Be not, plus B comes team. We can apply this contract equation because we're also told that the acceleration is constant throughout this trip. If the acceleration is not constant, predator and we cannot use this contract equation and most other kin O Matic equations and so X My sex, not a seventy v Nona's are unknown. V is fifteen and six. Selling for being on this equation gives us that V not is a point three three meters per second, which is the answer to party, Herbie. As for the acceleration to get the acceleration and we can use another Cammack equation, the mice bean on is equal to eight times t Is there a known We know we know. We know we not now on he's also know so we can plug it in fifteen for me a point three three for me non in six fourteen. Selling for a gives one point one one meters per second squared, which is the final answer.