displaystyle{x}={4};{y}={0} Explanation: displaystyle{3}cdot{x}-{y}={12}{left({1}

ight)}displaystyle{5}cdot{x}+{2}cdot{y}={20}{left({2}

ight)} Multiplying (1) by 2 we get …

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How do you solve the system of equations displaystyle{6}+{y}={2}{x} and displaystyle-{3}{x}-{y}={1} ?

displaystyle{x}={1},{y}=-{4} Explanation:Method: Rearrange the equations and solve by substitution. displaystyle{6}+{y}={2}{x}displaystyle{y}={2}{x}-{6}—- Equation 1 displaystyle-{3}{x}-{y}={1} …

How do you find the solution of the system of equations displaystyle{3}{x}-{y}={10} and displaystyle-{x}+{y}=-{4} ?

https://socratic.org/questions/how-do-you-find-the-solution-of-the-system-of-equations-3x-y-10-and-x-y-4

Don't Memorise May 2, 2015 We can add the two equations to eliminatedisplaystyle{y} Adding the 2 equations will give us: displaystyle{left({3}{x}-{y}

ight)}+{left(-{x}+{y}

ight)}={10}-{4} …

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3x-y=13 Geometric figure: Straight Line Slope = 3 x-intercept = 13/3 = 4.33333 y-intercept = 13/-1 = -13.00000 Rearrange: Rearrange the equation by subtracting what is to the right of …

3x-y=14 Geometric figure: Straight Line Slope = 3 x-intercept = 14/3 = 4.66667 y-intercept = 14/-1 = -14.00000 Rearrange: Rearrange the equation by subtracting what is to the right of …

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From the graphs, the intersection points aredisplaystyle{left({4},-{6}

ight)} , so the answer isdisplaystyle{x}={4}anddisplaystyle{y}=-{6} Explanation:standard linear equation …

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left< egin{array} { l l } { 2 } & { 3 } \ { 5 } & { 4 } end{array} ight> left< egin{array} { l l l } { 2 } & { 0 } & { 3 } \ { -1 } & { 1 } & { 5 } end{array} ight>

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